What a week it was for JuJu Smith-Schuster -- and now, the cherry on top.
The Steelers' rookie wide receiver was named the AFC Offensive Player of the Week after catching seven balls for 193 yards and a touchdown against the Lions.
BREAKING: @steelers rookie JuJu Smith-Schuster was named the AFC Offensive Player of the Week after his 7 rec, 193 yd, TD performance pic.twitter.com/HR2y5ipRUH
— Chase Williams WPXI (@chasepwilliams) November 1, 2017
Smith-Schuster responded nicely after being involved in several off-the-field incidents, such as being thrown under the bus by his teammate Martavis Bryant and having his bike stolen just days before his breakout game on Sunday Night Football.
Smith-Schuster is quickly proving he can be another big-play threat for the Steelers offense, but also showing he is a kid at heart while he's doing it.
After scoring the longest passing play in team history, the rookie pulled out a bike chain and tied up the stationary bike on the Steelers' sidelines, showing that nobody can take his bike now.
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Smith-Schuster and the Steelers are off this week but will get back on the field Nov. 12 in Indianapolis to take on the Colts.
Smith-Schuster becomes the first Steelers rookie to win AFC Offensive Player of the Week honors since Ben Roethlisberger won it in Week 6 in 2004. He leads the NFL's 2017 rookie class in receiving yards (424) and touchdown catches (4) through Week 8.
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