Steelers quarterback Ben Roethlisberger was named AFC Offensive Player of the Week for his Week 2 performance.
Roethlisberger was 21-of-27 for 369 yards and three touchdowns (passer rating of 155.8) against the San Francisco 49ers.
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Sunday was No. 7's 39th career 300-yard game during the regular season and the 31st time he threw at least three touchdowns in a single game during the regular season.
Roethlisberger has thrown at least one touchdown pass in 33 straight home games, which is the second-longest active streak and the sixth-longest streak in NFL history.
This marks the 12th time Roethlisberger has been named AFC Offensive Player of the Week and the first time since taking home such honors in back-to-back weeks (Weeks 8-9) in 2014.
WPXI